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What is the size angle of a pentagon?

What is the size angle of a pentagon?

108°

Pentagon
An equilateral pentagon, i.e. a pentagon whose five sides all have the same length
Edges and vertices 5
Internal angle (degrees) 108° (if equiangular, including regular)

What is the size of an interior angle of a regular 5 sided polygon?

The General Rule

If it is a Regular Polygon (all sides are equal, all angles are equal)
Shape Sides Each Angle
Triangle 3 60°
Quadrilateral 4 90°
Pentagon 5 108°

How do you find the measure of an interior angle in a regular polygon?

Let’s recap. A regular polygon is a flat shape whose sides are all equal and whose angles are all equal. The formula for finding the sum of the measure of the interior angles is (n – 2) * 180. To find the measure of one interior angle, we take that formula and divide by the number of sides n: (n – 2) * 180 / n.

What are the interior angles of a regular polygon?

The interior angles of a polygon are equal to a number of sides. Angles are generally measured using degrees or radians. So, if a polygon has 4 sides, then it has four angles as well….Interior angles of Regular Polygons.

Regular Polygon Name Each interior angle
Triangle 60°
Quadrilateral 90°
Pentagon 108°
Hexagon 120°

What is the size of each interior angle of a regular polygon?

The interior angles of a regular polygon are all equal to 140°.

What is an interior angle of a pentagon?

Pentagon/Internal angle

What is the interior angle of a regular polygon?

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